Math, asked by roxygaming2863, 1 month ago

If A is a 2x2 order matrix with 1st row [X-8 ] and 2nd row [28] is a singular matrix then the value
of x is
|​

Answers

Answered by honeyawan007
0

Answer:

8x+16=0

8x=-16

X=-2 so the value of x is - 2

Answered by bommuchakravarthilm
0

Answer:

The value of X=-2.

Step-by-step explanation:

Given matrix is

A=\left[\begin{array}{ccc}X&-8\\2&8\end{array}\right]

Singular Matrix: A matrix is said to be singular if the determinant of that matrix is zero.

The determinant of the matrix A is:

|A|=8X-(-8)(2)

Equate it to zero, since it is a singular matrix.

Perform multiplication for the second term.

8X+16=0

Take 16 to Right Hand side.

8X=-16

Take 8 to Right Hand Side

X=\frac{-16}{8}

Perform division. We get,

X=-2.

Therefore, the value of X is -2.

Similar questions