Math, asked by pavanchoudhary271020, 10 hours ago

If A is a 3X3 order matrix with 1st row [2 -1 3 ] and 2nd row [O 4 2] and 3rd row [1-1-2] then value of minor M11 is

-3

-6

-8

-9​

Answers

Answered by gandhinityam1
0

Answer:

-3 is right ans okk bro make me brainlist okk byy

Answered by bommuchakravarthilm
0

Answer:

Option B is correct: -6 is the  value of minor M11.

Step-by-step explanation:

We are given a matrix  A whose order is 3×3.

Elements in first row is [2 -1 3].

Elements in second row is [0 4 2].

Elements in third row is [1 -1 -2].

Therefore the matrix A is,

A=\left[\begin{array}{ccc}2&-1&3\\0&4&2\\1&-1&-2\end{array}\right]

We are asked to find the value of minor M11.

That means we have to find the value of minor in first row first column that is 2.

M11=A_{22} A_{33} -A_{23} A_{32}

A_{22} =4

A_{33} =-2

A_{23} =2

A_{32} =-1

Substitute the values in the above formula to get the value of minor of 2.

M_{11} =4(-2)-2(-1)

       =-8+2

       =-6

Therefore, the value of minor M11 is -6.Therefore Option B is correct.

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