Math, asked by keerthana608, 9 months ago

if A is a event of random exp such that P,(A):P(A) =1:2FIND VALUE OF P(A)BAR

Answers

Answered by vivekkumar1765
0

Answer:

1/2

Step-by-step explanation:

p(A) + p(A) bar = 1

1/2 + p(A)bar = 1

p(A) bar = 1-1/2

= 1/2

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