if A is a matrix
of order 3×3 and |A|=10, then |adjA| is
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Step-by-step explanation:
Consider the following identity A(adjA)=∣A∣I. Thus comparing it with the above equation gives us ∣A∣=10
Now ∣adjA∣=∣A∣
n−1
where n is the order of the square matrix.
Here 'n' is 3, therefore, ∣adjA∣=∣A∣
3−1
=∣A∣
2
=10
2
=100.
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