Question

If 'a' is a natural number, what will come in the unit's place in (53a + 84a) 4a

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Answer 1

Step-by-step explanation:

(53a + 84a) 4a= 137a*4a= 548a^2= 23.41a

Answer 2

Given:

Number = ( 53a + 84a ) 4a and 'a' is a natural number.

To Find:

What will be the digit in the unit's place?

Solution:

We can simply solve this numerical problem by using the following process.

Given that  ( 53a + 84a ) 4a

⇒ ( 137a ) 4a

⇒ 548 a²

1. Now let's assume every digit possible for a one by one in units place:
2. If a → 1 or 9 in units place then a² → 1 in units place then 8 × 1 = 8 is the digit in units place for (53a + 84a) 4a.
3. If a → 2 or 8 in units place then a² → 4 in units place then 8 × 4 = 24, 4 is the digit in units place for (53a + 84a) 4a.
4. If a → 3 or 7 in units place then a² → 9 in units place then 8 × 9 = 72, 2 is the digit in units place for (53a + 84a) 4a.
5. If a → 4 or 6 in units place then a² → 6 in units place then 8 × 6 = 48, 8 is the digit in units place for (53a + 84a) 4a.
6. If a → 5 in units place then a² → 5 in units place then 8 × 5 = 80, 0 is the digit in units place for (53a + 84a) 4a.
7. If a → 0 or 10 in units place then a² → 0 in units place then 8 × 0 = 0, 0 is the digit in units place for (53a + 84a) 4a.

The above-stated digits will be in unit place for different values of a.

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