if a is a root of the equation x2 -(a+b)x + K = 0 find the value of k
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@=a
x2-(a+b)x + k=0
put x=a in above equation
a2-(a+b)a+k=0
a2-(a2+ab) +k=0
a2-a2-ab+k=0
-ab+k=0
k=ab
x2-(a+b)x + k=0
put x=a in above equation
a2-(a+b)a+k=0
a2-(a2+ab) +k=0
a2-a2-ab+k=0
-ab+k=0
k=ab
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