if a is a singular,then inverse of lambda =?
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Answer:
∣A∣=0 as the matrix A is singular.
∴∣A∣=
∣
∣
∣
∣
∣
∣
∣
∣ 1
2
3
3
4
5
λ+2
8
10
∣
∣
∣
∣
∣
∣
∣
∣
∣
=0
Apply R
2
2
2 →R
2
2
2 −2R
1
1
1 and R
3
3
→R
3
−3R
1
1
1 and expand.
−2(4−λ)+4(4−2λ)=0
⇒8−2λ=0
⇒λ=4
For λ=4, the second and the third column are proportional.
.......
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