if a is a singular then lambda(1a)^-1=
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Answer:
A−Iλ is a singular matrix
⇒A−Iλ=0
⇒[1232]−λ[1001]=0
⇒[1232]−[λ00λ]=0
⇒∣∣∣∣∣∣1−λ232−λ∣∣∣∣∣∣=0
⇒(1−λ)(2−λ)−6=0
⇒2−λ−2λ+λ2−6=0
⇒λ2−3λ−4=0
⇒λ2−4λ+λ−4=0
⇒λ(λ−4)+1(λ−4)=0
⇒(λ−4)(λ+1)=0
Correct option is
A
λ=4
B
λ2−3λ−4=0
C
λ=−1
i hope my answer is correct any doubt you can ask me thank you
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