Question

If a is a skew symmetric matrix of order 3 then prove that det a=0

Answer 1

and skew symmetric matrix has contain the diagonal elements are 0

Answer 2

Answer:

A is skew symmetric

→ A = -$A^{T}$

→ |A| = - |A|                 { ∴ |A| = |$A^{T}$| }

→ 2|A| = 0

→ |A| = 0

 Therefore, det A = 0

Good luck !!