If ''-a'' is a solution of the equation x^2 + 3ax+k = 0, find the value of k. Thus, find the other root of the equation
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Step-by-step explanation:
x2+3ax+k=0
Substituting x=−a,
⇒ (−a)2+3a(−a)+k=0
⇒ a2−3a2+k=0
⇒ −2a2+k=0
⇒ k=2a2
Now substituting k=ma2
⇒ ma2=2a2
∴ m=2
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