If A is a square matrix of order 3 such that A(adj A) = 10 I where I is the identity matrix of order 3, then |adj A|
is equal to.
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Answer:
|adj A|=(10)^(2/3)
Step-by-step explanation:
A(adj A) =10 I
So,
|A(adj A) |=10
|A|×|(adj A) |=10
Now, |(adj A)|=|A|^(n-1)
Where n is the order of the matrix,
Here n=3 so,
|adj A|=|A|^2
i.e
|A|×|A|^2=|A|^3=10
|A|=(10)^(1/3)
So
|adj A|=(10)^(2/3)
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