If A is a square matrix of order 3, such that A(adjA) =10I , then (adjA) is equal to
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Step-by-step explanation:
Given If A is a square matrix of order 3, such that A(adjA) =10 I , then (adjA) is equal to
- Consider the equation A (adj A) = lAl I
- Given A (adj A) = 10 I
- Comparing this with the general equation we get
- So l A l = 10
- We know that ladj Al = l Al^n-1 where n is the order of matrix.
- = l A l ^3 -1 (since order of matrix is 3)
- = l Al^2
- = 10^2
- = 100
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A is a square matrix of order 3, such that A(adjA) =10I , then (adjA) is equal to
Given,
A(adjA) =10I
⇒ |A| = 10
We have formula for calculating the adjoint of a matrix, given by,
|adj (A)| = |A|^{n-1}
where, n = order of the square matrix
As given n = 3, so we get,
|adj (A)| = |A|^{3-1}
|adj (A)| = |A|^{2}
as |A| = 10
|A|^{2} = 10^2
|A|^{2} = 100
Therefore (adjA) is equal to 100
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