Math, asked by naman45155, 11 months ago

If A is a square matrix of order 3, such that A(adjA) =10I , then (adjA) is equal to​

Answers

Answered by knjroopa
29

Step-by-step explanation:

Given If A is a square matrix of order 3, such that A(adjA) =10 I , then (adjA) is equal to

  • Consider the equation A (adj A) = lAl I
  • Given A (adj A) = 10 I
  • Comparing this with the general equation we get
  • So l A l = 10
  • We know that ladj Al = l Al^n-1 where n is the order of matrix.
  •                                  = l A l ^3 -1 (since order of matrix is 3)
  •                                  = l Al^2
  •                                   = 10^2
  •                                  = 100

Reference link will be

https://brainly.in/question/9949388

Answered by AditiHegde
9

A is a square matrix of order 3, such that A(adjA) =10I , then (adjA) is equal to​

Given,

A(adjA) =10I

⇒ |A| = 10

We have formula for calculating the adjoint of a matrix, given by,

|adj (A)| = |A|^{n-1}

where, n = order of the square matrix

As given n = 3, so we get,

|adj (A)| = |A|^{3-1}

|adj (A)| = |A|^{2}

as |A| = 10

|A|^{2} = 10^2

|A|^{2} = 100

Therefore (adjA) is equal to​ 100

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