Math, asked by pvpatel2004pp, 1 month ago

if A is a square matrix of order n and A=kB where k is a scalar then IAI=

a. IBI
b. KIBI
c. K^nIBI
d. nIBI​

Answers

Answered by shettysulaksha75
0

Answer:

K^ n|B| is the correct answer

Answered by Manmohan04
0

Given,

A is a square matrix of order n.

\[A = kB\], where k is a scalar.

Solution,

It is given that square matrix has order of n. So it has n rows and n column.

\[A = kB\]

To satisfy the above condition both matrix should have same order.

k is the scalar that is taken common from each row. There are n rows so k will be \[{k^n}\].

So the determinant will be,

\[|A| = {k^n}|B|\]

Hence the correct option is (c), i.e. \[|A| = {k^n}|B|\]

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