If A is a square matrix such that A2=A, then write the value of 7A−(I+A)3 where I is an identity matrix.
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Answered by
0
Answer:
given A2=A
7A−(I+A)3=7A−[I3+3A2I+3AI2+A3]
=7A−[I+3A+3A+A2.A]
=7A−[I+3A+3A+A]
=7A−I+7A
=−I
Answered by
2
Answer:
given A2=A
7A−(I+A)3=7A−[I3+3A2I+3AI2+A3]
=7A−[I+3A+3A+A2.A]
=7A−[I+3A+3A+A]
=7A−I+7A
=−I
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