If A is a subset of B and C is a subset of D , then prove that A x C is a subset of B x D
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Given
- A ⊂ B ⟺ {x ∈ A ⟹ x ∈ B}
Similarly,
- C ⊂ D ⟺ {x ∈ C ⟹ x ∈ D}
To Prove
- A × C ⊂ B × D.
That is, we want to prove the implication
( y , z ) ∈ A × C ⟹ ( y , z ) ∈ B × D.
Suppose that
( y , z) ∈ A × C.
This implies that
{ y ∈ A } ∧ { z ∈ C}.
Consequently,
{ y ∈ B } ∧ { z ∈ C }
is also True, since A ⊂ C and B ⊂ D.
Finally,
( y , z ) ∈ B × D.
Since y and z were arbitrary, we have proved that
A × C ⊂ B × D .
✌✌Proved
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A x C is a subset of B x D
Given: A⊂B and C⊂D
To prove: A x C ⊂ B x D
Let (a,c) ∈ AXC
⇒ a∈A and c∈C
⇒ a∈B and c∈D
Since A is the subset of B, so the elements of A is present in B, same goes with c∈D as set C is the subset of D
⇒(a,c) ∈ BxD
⇒ if (a,c)∈ AXC, then (a,c) ∈ BXD.
⇒AXC ⊂BXD
Hence proved
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