Question

If A is acute and cos²A/cot²A-cos²A=3, then A is equal to​

Answer 1

Answer:

here is your answer mate

Step-by-step explanation:

Let triangle ABC be a right angled at B and A is a acute angle.

Given that cosec A = √2

Which implies,

AC/BC=√2/1

Let AC = √2x

Then BC = x

In right angled triangle ABC

By using Pythagoras theorem,

We get

AC

2

=AB

2

+BC

2

(√2x)

2

=AB

2

+x

2

AB

2

=ax

2

−x

2

AB=x

sin A = perpendicular/ hypotenuse

= BC/AC

=1/√2

Cot A = base/ perpendicular

=x/x

=1

Tan A = perpendicular/ base

=BC/AB

=x/x

=1

Cos A = base/ hypotenuse

=AB/AC

=x/√2x

=1/√2

substituting these values we get

2sin

2

A+3cot

2

A/(tan

2

A−cos

2

A)=8

Answer 2

Answer:

adi

Step-by-step explanation:

Explanation:

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