Question

If A is acute and cosA=3/5,then find Sin2A, Cos3A and tan2A

Answer 1

sinA=√1-cosA^2

sinA=4÷5

sin2A=2xcosAxsinA=24/25

cos2A=2cosA^2-1=7/25

tan2A=sin2A/cos2A=(24/7)

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