Question

if A is am between a and b prove that 4(a-A)(A-b) = (b-a)^2​

Answer 1

Answer:

Step-by-step explanation:

A=(a+b)/2

LHS:

4(a-A)(A-b)

4(a-((a+b)/2))(((a+b)/2)-b))

4((2a-a-b)/2)((a+b-2b)/2)

4(a-b)/2*(a-b)/2

4*(a-b)^2/4

(a-b)^2

=RHS