Question

If A is an acute angle and
sin A= cos A, find the value of :
2 tan² A + sin²A - 1​

Answer 1

Answer:

3/2

Step-by-step explanation:

given sinA= cosA

we know that cosA=sinA

when A=45°

now putting A=45°

=2 tan^45° + sin^2 45° -1

tan45°=1 and sin45°=1/√2

putting values

=2*1 +(1/√2)^2 -1

=2+(1/2) -1

=3/2

Answer 2

Answer:

sinθ=cosθ

cosθ

sinθ

=

cosθ

cosθ

tanθ=1=tan45

o

θ=45

o

Therefore, 2tan

θ

+sin

2

θ−1=2tan

4

5

o

+sin

2

45

o

−1

=2×(1)

2

+(

2

1

)

2

−1=2+

2

1

−1=

2

3

.