Math, asked by agnesp2305, 4 months ago

If ∠A is an acute angle and tanA=√6+2/√6−2, find cosA.

Answers

Answered by deerajdr2
0

Answer:

This may help you

Step-by-step explanation:

tanA=  

3

​  

 

1

​  

 

sinB=  

2

1

​  

 

cos(A+B)=?

cos(A)

sinA

​  

=  

2

1

​  

×  

3

​  

 

2

​  

 

sinA=  

2

1

​  

sinB=  

2

1

​  

⇒B=30  

0

 

cosA=  

2

3

​  

 

​  

=A=30  

0

 

cos(A+B)=cos(30  

0

+30  

0

)

=cos60  

0

=  

2

1

​  

Ans.

Answered by aditisabharwal
0

Answer:

cosA = 1/√2

Step-by-step explanation:

sum is explained in detail in the picture

hope it's help you✌

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