if a is an acute angle find sin3A = cos 2A
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Answer:
16 degrees
Step-by-step explanation:
= sin3A=sin(90-2A)
as sin= sin cancel sin from lhs and rhs
= 3A=90-2A
= 3A + 2A = 90
= 5A = 90
= A = 90/5
= A = 16
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