if a is an acute angle of a triangle ABC right angled at B the value of Sin A + cos A
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In right ∆ABC , right angled at B :-
=)sin A = P/H = BC/AC
=)cos A = B/H = AB/AC
=)sinA + cosA = AB+BC/ AC
Hope it helps.
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=)sin A = P/H = BC/AC
=)cos A = B/H = AB/AC
=)sinA + cosA = AB+BC/ AC
Hope it helps.
Mark as brainliest
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