Math, asked by srinivasaraojami1981, 9 months ago

if a is an even natural number such that a divides 208 and (a, b) =1 then find the value of b​

Answers

Answered by gbhavanishankar
2

i am writting answer for"if a is an even natural number such that a divides 208 and a-b=1, the find the value of b"

Answer:

the answers for the value of b are 1,51,25 and so on

Step-by-step explanation:

Answered by syed2020ashaels
1

b is equal to all the odd integers of the number system which includes 3, 5, 7, etc.

Step-by-step explanation:

  • 208 can be factorized as,

       208 = 2*2*2*2*13

  • Now, a must be an even natural number such that a divides 208, hence a must be one of the factors of 208 and a must also be an even natural number.
  • Therefore, since 2 is the only even natural number in the factorization of 208, a is evidently equal to 2.
  • Now, according to the given information, (a,b)=1 and a=2. Therefore, the integers that are prime to a are all the odd integers in the number system. That is, b is equal to all the odd integers of the number system which includes 3, 5, 7, etc.

Hence, b is equal to all the odd integers of the number system which includes 3, 5, 7, etc.

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