Math, asked by samrudhi0354, 11 months ago

If A is an event of a random experiment, such that P(A):P(Ā) =1:2, find the value of P(A)

Answers

Answered by geethamoorthi2002
0

Answer:

3/3=p(a) A=1 the answer is 1

Answered by tennetiraj86
40

Answer:

\huge{\boxed{\rm{\red{P(A)=1/3}}}}

Step-by-step explanation:

Given :-

A is an event of a random experiment, such that P(A):P(Ā) =1:2,

To find:-

find the value of P(A)

Using formula:-

P(A)+P(Ā) =1

Solution:-

A is an event of a random experiment

such that P(A):P(Ā) =1:2, find the value of P(A)

such that P(A):P(Ā) =1:2, find the value of P(A)Let P(A)=1k=k

P(Ā) =2k

Now,

P(A)+P(Ā) =1

=>k+2k=1

=>3k=1

=>k=1/3

Now

P(A)=k=1/3

Answer:-

The value of P(A)=1/3

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