Question

if a is an event of and random experiment such that P (A) : p ( A)is equal to 1 : 2 find the value of P (A)​

Answer 1

Answer:

Here's the answer ^^

Step-by-step explanation:

According to the given ratio, the total number of events from the experiments is equal to the sum of the ratios which is 1 + 2=3

Probability = number of outcomes / total number of outcomes.

P(A) for the first one is 1/3 meaning the number of outcomes or rather events is equal to 1.

P(A) for the second one is 2/3 meaning the number of outcomes or events is 2.

Answer 2

Answer:

Value of P(A') is 11/16

Step-by-step explanation:

Given that,

P(A) P(A')

$\frac{P(A)}{P(A')} = \frac{5}{11}$

We know that,

$P(A') = 1 - P(A)$

Now,

$\frac{P(A)}{1 - P(A)} = \frac{5}{11} \\ 11P(A) = 5 - 5P(A) \\ 16P(A) = 5 \\ P(A) = \frac{5}{16} \\ and \: P(A') = 1 - P(A) = 1 - \frac{5}{16}$

So,

$P(A') = \frac{11}{16}$