Math, asked by yewaleanuj03, 9 months ago

If a is an integer lying in the closed interval (-5,30), then the probability that the
graph of y=x2+2(a+4) x-5a+64 is strictly above the x-axis is

Answers

Answered by Anonymous

Answer:

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Answered by aaabbb18

If a is an integer lying in the closed interval (-5,30), then the probability that the
graph of y=x2+2(a+4) x-5a+64 is strictly above the x-axis is

Answers

ans is 21.

step by step explaination

Given a∈I and a∈[−5,30]

⇒y=x2+2(a+4)x−5a+64

a can assume values from −5 to 30.

⇒y=x2+2(a+4)x−5a+64>0 for all a∈I and x∈R

disc<0 i.e, b2−4c<0

=[2(a+4)]2−4[−(5a+64)]

=a2+18a+144.

∴ The roots are (−a,a), this point denotes that the graph is below x−axis.

∴ The probability of rest of points being strictly above the x−axis =21.

Hence, the answer is 21.

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hope it helps u ✌

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mark me as brainliest

If a is an integer lying in the closed interval (-5,30), then the probability that thegraph of y=x2+2(a+4) x-5a+64 is strictly above the x-axis is​

Answers

ans is 21.

step by step explaination

Given a∈I and a∈[−5,30]

⇒y=x2+2(a+4)x−5a+64

a can assume values from −5 to 30.

⇒y=x2+2(a+4)x−5a+64>0 for all a∈I and x∈R

disc<0 i.e, b2−4c<0

=[2(a+4)]2−4[−(5a+64)]

=a2+18a+144.

∴ The roots are (−a,a), this point denotes that the graph is below x−axis.

∴ The probability of rest of points being strictly above the x−axis =21.

Hence, the answer is 21.

-------------------------------✌✌

hope it helps u ✌

-------------------------------✌✌

mark me as brainliest

If a is an integer lying in the closed interval (-5,30), then the probability that the
graph of y=x2+2(a+4) x-5a+64 is strictly above the x-axis is