IF
a
IS
AN
ODD
INTEGER, SHOW THAT
a^4 + [a+2] ^3 [a+4]^2+1
is an INTEGER
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1
Answer:
a^4+(a^3+8+6a^2+12a)(a^2+16+8a)+1
=a^4+a^5+8a^2+6a^4+12a^3+16a^3+128+96a^2+192a+8a^4+64a+48a^3+96a^2+1
=129+256a+200a^2+76a^3+17a^4+a^5
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