Math, asked by surtipearl7001, 9 months ago

If a is coded as + b is coded as minus c is coded as multiply and d is coded as divide then evaluate 8 a 32 c 24 b 4c3

Answers

Answered by EliteSoul
97

Answer:

\: \: \: \:  \: \blue{\underline{\red{\boxed{\mathfrak\green{Answer = 764}}}}}

Question:-

If a is coded as + , b is coded as - , c is coded as multiply, d is coded as division.Then evaluate:-

→ 8 a 32 c 24 b 4c3

Solution:-

Given:-

  • a = +
  • b = -
  • c = ×
  • d = ÷

To find:-

  • 8 a 32 c 24 4c3

Putting the values:-

\sf 8 + 32 \times 24 - 4 \times 3

\scriptsize\sf\blue{\: \: \: \: \dag Using\: 'BODMAS' \: theorem:- }

\sf 8 + 768 - 12

\sf 776 - 12

\large{\boxed{\sf\blue{764}}} - - - - - -  [\sf Answer!]

Some trigonomatric identities:-

  • \rm \sin^2 \theta + \cos^2 \theta = 1

  • \rm \sec^2 \theta = 1 + \tan^2 \theta

  • \rm \csc^2 \theta = 1 + \cot^2 \theta

  • \rm \tan \theta =\dfrac{\sin\theta}{\cos \theta}

  • \rm \cot \theta =\dfrac{\cos\theta}{\sin \theta}

BrainlyConqueror0901: keep helping buddy : )
VishalSharma01: Nice Ansewr
SnowySecret72: Great:)
Answered by Anonymous
70

AnswEr :

764

\bf{\Large{\green{\underline{\underline{\bf{Given\::}}}}}}

If a is coded as (+),

b is coded as (-),

c is coded as (×),

d is coded as (÷).

8 a 32 c 24 b 4 c 3.

\bf{\Large{\red{\underline{\underline{\bf{To\:find\::}}}}}}

Evaluate that.

\bf{\large{\blue{\underline{\underline{\tt{Explanation\::}}}}}}

\bf{\large{\purple{\underline{\sf{\dag\:{According\:to\:BODMAS\:rule\::}}}}}}}}}}}}

\dashrightarrow\tt{8\:a\:32\:c\:24\:b\:4\:c\:3}\\\\\\\dashrightarrow\tt{8+32\times 24-4\times3}\\\\\\\dashrightarrow\tt{8+768-12}\\\\\\\dashrightarrow\tt{776-12}\\\\\\\dashrightarrow\tt{\red{764}}

________________________________________

\bf{\Large{\green{\underline{\underline{\sf{B.O.D.M.A.S\::}}}}}}

\sf{\green{\large{\bullet{\bf{B=Brackets}}}}}}}\\\\\\\sf{\green{\large{\bullet{\bf{O=Of}}}}}\\\\\\\sf{\green{\large{\bullet{\bf{D=Divide}}}}}}}\\\\\\\sf{\green{\large{\bullet{\bf{M=Multiplication}}}}}}}\\\\\\\sf{\green{\large{\bullet{\bf{A=Addition}}}}}}}\\\\\\\sf{\green{\large{\bullet{\bf{S=Subtraction}}}}}}}


VishalSharma01: Nice Answer
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