if A is directly proportional to C and B is directly proportional to C prove that each of the following is directly proportional to C
(a)A+B
(b)A-B
(c)√AB
Answers
Answer:
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Step-by-step explanation:
A=kC
B=jC
A+B= kC +jC = (k+j)C k+j is a constant, so A+B = mC where m=k+j
A-B = kC-jC = (k-j)C k-j is a constant, so A-B = nC where n=k-j
sqrAB = sqrAsqrB = sqrkCsqrjC = sqrkjC
square both ends
sqrAB^2 = sqrkjC^2
AB = kjC kj is a constant,
AB =pC where p =kj, a constant
Given : A is directly proportional to C and B is directly proportional to C
To Find : prove that each of the following is directly proportional to C
Solution:
A is directly proportional to C
A ∝ C
=> A = mC
m is constant
B is directly proportional to C
B ∝ C
=> B = nC
n is constant
A + B = mC + nC
=> A + B = ( m + n ) C
m + n is constant
=> A + B ∝ C
A - B = mC - nC
=> A - B = ( m - n ) C
m - n is constant
=> A - B ∝ C
√AB = √mCnC
=> √AB = √mn *C
√mn is contant
Hence √AB ∝ C
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