if a is equal to 2 + under root 3 prove that: a square minus 4a + 1 is equal to zero
tejasgupta:
hmmm
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a=2+√3
a²-4a+1=0
Solution
a²-4a+1
(2+√3)²-4(2+√3)+1
(2²+(√3)²+2*2*√3)-8-4√3+1
4+3+4√3-8-4√3+1
7+4√3-4√3-8+1
7-8+1
-1+1
= 0
a²-4a+1=0
Solution
a²-4a+1
(2+√3)²-4(2+√3)+1
(2²+(√3)²+2*2*√3)-8-4√3+1
4+3+4√3-8-4√3+1
7+4√3-4√3-8+1
7-8+1
-1+1
= 0
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