Question

If a is equal to 3- root 5 divided by 3 + root 5 and b is equal to3+ root 5 divided by 3- root 5, find a square-b square​

Answer 1

Step-by-step explanation:

solve it by yourself..

hope ot hepls

Answer 2

Answer:

$-21\sqrt{5$

Step-by-step explanation:

$a^2 - b^2 = (a+b)(a-b)$

$a = \frac{3- \sqrt{5} }{3 +\sqrt{5} } }$

$b = \frac{3 + \sqrt{5} }{3 - \sqrt{5} }$

a + b = $(3-\sqrt{5}) ^{2} +( 3 + \sqrt{5})^2}/(3+\sqrt{5})(3-\sqrt{5})$

Therefore, a + b = 7

similarly

a - b = $-3\sqrt{5}$

Now,

$a^2 - b^2 = -21\sqrt{5$

Thank You!!