if a is equal to 6 + 2 root 3 find the value of a minus one by a
Answers
Hey there!!
a = 6 + 2√3
a - ( 1 / a ) = ?
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1 / a = 1 / 6 + 2√3
( 1 ÷ 6 + 2√3 ) × ( 6 - 2√3 ÷ 6 - 2√3 )
In the denominators ,
Using the identity
( a + b ) ( a - b ) = a² - b²
( 6 - 2√3 ) ÷ ( 6 + 2√3 × 6 - 2√3 )
( 6 - 2√3 ) ÷ ( 36 - 12 )
( 6 - 2√3 ) ÷ ( 24 )
a - ( 1 ÷ a )
( 6 + 2√3 ) - ( 6 - 2√3 ÷ 24 )
[ 24 ( 6 + 2√3 ) - ( 6 - 2√3 ) ] ÷ 24
( 144 + 48√3 - 6 + 2√3 ) ÷ 24
( 138 - 50√3 ) ÷ 24
2 ( 69 - 25√3 ) ÷ ( 2 ) ( 12 )
69 - 25√3 ÷ 12
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ANS :-
( 69 - 25√3 ) / 12
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