if a is equal to one b is equal to minus 2 C is equal to minus 3 then find the value of a cube plus b cube plus c cube - 3abc is divided by a b + BC + CA - bracket make a square + b square + c square bracket close
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Answered by
19
a=1
b=-2
c=-3
a^3+b^3+c^3-3abc
=1^3+(-2)^3+(-3)^3-3(1)(-2)(-3)
=1-8-27-3(6)
=-34-24
=-58
b=-2
c=-3
a^3+b^3+c^3-3abc
=1^3+(-2)^3+(-3)^3-3(1)(-2)(-3)
=1-8-27-3(6)
=-34-24
=-58
Answered by
12
a = 1
b = -2
c = -3
a³ + b³ + c³ - 3abc = ?
Put the values and you will get the answer!
1³ + (-2)³ + (-3)³ - 3×1×(-2)×(-3) = 1-8-27-18 = -52
b = -2
c = -3
a³ + b³ + c³ - 3abc = ?
Put the values and you will get the answer!
1³ + (-2)³ + (-3)³ - 3×1×(-2)×(-3) = 1-8-27-18 = -52
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