If a is equal to root 2 X + 3 Y + root 2 x minus 3 Y upon root 2 X + 3 Y - root 2x - 3y find the value of 3 y a square - 4 x 8 + 3 y.
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Answer:
√2x+√3y=0--(1)
√3x-√8y=0---(2)
Multiply (1) by √3 and (2) by √2
√6x+√9y=0----(3)
√6x--√16y=0---(4)
subtracting (4) from (3)
√9y+√16y=0
y=0
From(1)
√2x+√3(0)=0
√2x=0
x=0
x=0,y=0
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♥️3x−2y2x+3y=56
18x−12y=10x+15y
8x=27y
x/y=27/8
[3√x+3√y3√x−3√y]2
(3√27+3√83√27−3√8)2
⇒(3+23−2)2=(5)2=25
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ɪ ʜᴏᴘᴇ ɪᴛ′s ʜᴇʟᴘ ᴜ:)
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