If a is equal to two ICAP + 2 J cap b is equal to 3 ICAP - 2 J cap and C is equal to 6 ICAP - 2 k cap then what would be the value of a minus 2 b + 3 C
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The value of 2b+3C is
24 icap-4 j cap-6 k cap
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0
Answer:
a - 2 b + 3 c = 13 i + 6 j - 6 k
Explanation:
Given that
a= i +2 j
b = 3 i -2 j
c= 6 i - 2 k
a - 2 b + 3 c= ?
Lets take R= a - 2 b + 3 c
R= (i +2 j ) - 2 (3 i -2 j) + 3(6 i - 2 k)
R= (i +2 j ) - 6 i + 4 j + 18 i - 6 k
R= (i +2 j ) - (6 i -4 j) + (18 i - 6 k)
R= i (1 - 6 +18) +j( 2 + 4 ) - 6 k
R = 13 i + 6 j - 6 k
a - 2 b + 3 c = 13 i + 6 j - 6 k
So we can say that a - 2 b + 3 c is equal to the 13 i + 6 j - 6 k.
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