If a is equal to x cube relative error in a would be how many times the relative error in x
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Answered by
5
It is given that, a = x³
we have to find the relation between relative error of a and relative error of x.
expression, a = x³
taking log both sides,
loga = logx³
or, loga = 3logx [ as we know, logsⁿ = nlogs ]
differentiating both sides,
or, da/a =3 × dx/x
if da comparable to a then, da → ∆a and similarly dx → ∆x
so, ∆a/a = 3 × ∆x/x
hence, relative error in a = 3 × relative error in x.
Answered by
7
Answer:
3 times
Step-by-step explanation:
If a is equal to x cube relative error in a would be how many times the relative error in x
a = x³
Δx error in x
Δa = error in a
a = x³
=> Δa/a = 3Δx/x
relative error in a would be 3 times the relative error in x
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