Question

if a is equals to 1 minus under root 2 find the value of a minus one upon a whole cube
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Answer 1

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Step by step solution:

$Given \ a=1-\sqrt{2}\\\\Now \ taking \ reciprocal \ of \ both\\\\\frac{1}{a} =\frac{1}{1-\sqrt{2} }\\\\Now \ rationalize \ it\\\\\frac{1}{a} =\frac{1}{1-\sqrt{2} }\times \frac{1+\sqrt{2}}{1+\sqrt{2}}\\\\\frac{1}{a} =\frac{1+\sqrt{2}}{1-2}\\\\\frac{1}{a} =-(1+\sqrt{2})\\\\we \ have \ find \ value \ of \ (a-\frac{1}{a} )^3\\\\(a+\frac{1}{a})=(1-\sqrt{2})-[-(1+\sqrt{2})\\\\(a+\frac{1}{a})=(1-\sqrt{2}+1-\sqrt{2})\\\\(a+\frac{1}{a})=2\\\\Now \ cubing \ both \ side\\\\(a+\frac{1}{a})^3=(2)^2=8$

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Answer 2

Answer:

Step-by-step explanation:

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