Question

if a is equals to 1 upon 2 minus root 3 find a + 1 upon a bracket Cube​

Answer 1

Answer:

Step-by-step explanation:

x+1/x = 3 .....(1)

Cubing both sides

(X+1/x)^3 = 27

we know, (a+b)^3 = a^3 + b^3 + 3a^2b + 3ab^2

x^3 + 1/x^3 + 3x^2*1/x + 3x*1/x^3 = 27

x^3 + 1/x^3 + 3x + 3/x = 27

x^3 + 1/x^3 + 3(x+1/x) = 27

using (1)

x^3 + 1/x^3 + 3(3) = 27

x^3 + 1/x^3 = 27 - 9 = 18