Math, asked by sushant20, 1 year ago

if a is equals to 9 by root 11 minus root 2 and b is equal to 6 by 3 root 3 then the relation between a and b is

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Answered by Argon288
11
ob viously root under 11 will be greater than 3 and less than4 and root under 2 is greater than one and less than two. Thus a= >4 &<5.
b will obviously be greater than square root 2 but less than square root 11. Also the fraction multiplied with square root 3 is less than one. So the result will be option 2 a>b
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sushant20: thank s for the help
Answered by Infinito
0

Answer: a>b

Step-by-step explanation:

a when simplified = \sqrt{11} +\sqrt{12}

b when simplified = 2/\sqrt{3}

\sqrt{11} +\sqrt{12} = 3.31 + 1.41 = 4.72

2/\sqrt{3} = 2/1.73 = 1.15

Therefore a > b

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