if a is equals to 9 by root 11 minus root 2 and b is equal to 6 by 3 root 3 then the relation between a and b is
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ob viously root under 11 will be greater than 3 and less than4 and root under 2 is greater than one and less than two. Thus a= >4 &<5.
b will obviously be greater than square root 2 but less than square root 11. Also the fraction multiplied with square root 3 is less than one. So the result will be option 2 a>b
b will obviously be greater than square root 2 but less than square root 11. Also the fraction multiplied with square root 3 is less than one. So the result will be option 2 a>b
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thank s for the help
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Answer: a>b
Step-by-step explanation:
a when simplified =
b when simplified =
= 3.31 + 1.41 = 4.72
= 2/1.73 = 1.15
Therefore a > b
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