Math, asked by yuvikabansal1010, 2 months ago

if A is greater than B B is greater than CC is greater than D, D is greater than is e are consecutive positive integers such that b + C + D is a perfect square A + B + C + b + c is the perfect to the smallest possible value is​

Answers

Answered by kamaljpsharma
0

Answer:

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Answered by farhaanaarif84
0

Answer:

Since the middle term of an arithmetic progression with an odd number of terms is the average of the series,

we know b+c+d=3c and a+b+c+d+e=5c.

Thus, c must be in the form of 3⋅x

2

based upon the first part

and in the form of 5

2

⋅y

3

based upon the second part, with x and y denoting an integers.

c is minimized if it’s prime factorization contains only 3,5,

and since there is a cubed term in 5

2

⋅y

3

, 3

3

must be a factor of c.

3

3

5

2

=675

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