Question

If a is not is equals to zero and a minus one upon a is equals to 3 find a square + 1 upon a square and a cube minus 1 upon a cube

Answer 1

x-(1/x)=3

and we have to find x³-(1/x³)

solution:

we know rhat,

(a-b)³=a³-b³-3ab(a-b)

here a=x and b=1/x

(x-1/x)³=x³-1/x³-3*x*1/x(x-1/x)

given (x-1/x)=3

therefore,

(3)³=x³-1/x³-3(3)

27=x³-1/x³-9

27+9=x³-1/x³

36=x³-x/x³

answer is 36

hope you understood

Answer 2

Step-by-step explanation:

1. a^2+ 1/a^2 is equal to 11.

2. a^3 - 1/ a^3 is equal to 36.