Question

if a is rational and √b is a irrational then prove that (a+√b) is irrational​

Answer 1

Answer:

√b here proves to be a rational number by taking r-as as p and s=q because p/q is a rational number. ... so our assumption is wrong, so a+√b is an irrational number.

Answer 2

$rational + irrational = irrational$

Step-by-step explanation:

$We \: \: know \: \: that \: \: the \: \: sum, \: difference, \: multiplication \: \: and \: \: division \: \: of \: \: a \: \: rational \: \: number \: \: and \: \: an \: \: irrational \: \: number \: \: is \: \: also \: \: an \: \: irrational \: \: number. \\ so \: \: \: a + \sqrt{b} \: \: is \: \: irrational \: \: number$