If a is subset of b then prove that a intersection b is equal to a
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Let set B=(,1, 2,3,4,5,6,7,8,9)
Set A=(2, 4,6,8)
Since A is subset of B
A intersection B=(2, 2,4,4,6,6,8,8)
But we don't repeat one number twice in a set therefore A intersection B=(2, 4,6,8) or A intersection B=A proved
Set A=(2, 4,6,8)
Since A is subset of B
A intersection B=(2, 2,4,4,6,6,8,8)
But we don't repeat one number twice in a set therefore A intersection B=(2, 4,6,8) or A intersection B=A proved
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