Question

if A is the singular then( lambda A)^-1 a)(lambda) A^-1 b)(one by lambda) A^-1 c) A^-1( lambda )^-1 d) ( lambda )^3 A^-1​

Answer 1

Answer:

∣A∣=0 as the matrix A is singular.

∴∣A∣=∣∣∣∣∣∣∣∣123345λ+2810∣∣∣∣∣∣∣∣=0

Apply R2→R2−2R1 and R3→R3−3R1 and expand.

−2(4−λ)+4(4−2λ)=0

⇒8−2λ=0 

⇒λ=4

For λ=4, the second and the third column are proportional.

Correct option is

4

i hope my answer is correct any doubt you can ask me thank you