If A is the sum of integer from 1 to 50 and B is the sum of integers from 51 to 100. what is B-A?
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Answer:
2500
Step-by-step explanation:
so
A or B = n/2 (a+l)
n=50 (for both)
a=1 (A) 51 (B)
l=50 (A) 100 (B)
B-A
= (50/2 (51+100))-(50/2 (1+50))
=25 (51+100-1-50)=25×(1+99)
=25×100=2500
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