if a is zero of the polynomial ax²-3(a-1)x-1 find the value of a
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Give: p(x)= ax2_3 (a_1) x_1
one of the zero =1
As one of the zeroes is 1, substituting it in the polynomial .
- p(1)=0=a_3(a_1) _1
- p= _ 2a + 3_1
- a=1
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