If A= (k 3 10 5) is a singular matrix
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Step-by-step explanation:
Give that :2×2 matrix
A= [ k 10]
3 5
To find :
value of K for which the give matrix A is singluar.
Solution:
A square matrix is said to be singular, if determinant of matrix is zero.
so, find the value of determinant and equate it to zero
|A| = 0
[k 10] =0
3 5
5K-30 =0
5K =30
K =30
5
K =6
THE VALUE OF K SHOULD BE 6,FOR THE MATRIX A TO BE SINGULAR.
I Think IT WILL HELP YOU
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