Question

If a ladder 20m long reaches a window 16m above the ground, then the distance of the foot of the ladder from the base of the wall is *

Answer 1

Step-by-step explanation:

H from ground = 16m

L of ladder = 20m

It forms a right angled triangle.

So, by using the Pythagoras theorem we will find the answer.

B = sq ( H^2-p^2 )

B = sq root ( 20^2-16^2 ) = 12m

Answer 2

★ Diagram :-

$\setlength{\unitlength}{1mm}\begin{picture}(0,0) \thicklines\put(0,0){\line(3,0){2.45cm}} \put(0,0){\line(0,3){2cm}} \put(0,19.6){\line(5,-4){2.4cm}} \put(0.2,0.3){\circle*{0.9}}\put(-3,-3){B}\put(24.6,0.2){\circle*{0.9}}\put(24.6,-3){C}\put(0,19.8){\circle*{0.9}}\put(-2,21){A} \put(-2,-10){\boxed{\bf @\: ItzArchimedes}}\put(13,12){\vector(4,3){1cm}}\put(23,21){\rm ladder = 16m}\put(6,-3){Land = ?}\put(-20,6){Wall = 20m}\end{picture}$

★ Given :-

• Length of ladder = 20 m
• Height of wall = 16 m

★ To find :-

• Distance from foot of the ladder to the base of the wall

★ Solution :-

From the given info it forms a right triangle

With

• Hypotenuse = 20 m
• Height = 16 m
• Base = ?

Now , finding distance form foot of the ladder to the base of the wall (Base) using pythagoras theorem

(Hypotenuse)² = (Base)² + (Height)²

→ 20² = Base² + 16²

→ 400 = Base² + 256

→ 400 - 256 = Base²

→ 144 = Base²

→ Base = √144

→ Base = 12 m

Hence , distance from foot the ladder to the base of the wall = 12 m