if a ladder of height 17m is kept on the street to reach the height of 8m window on one side oh the house and from the same point one the other side 15m window, find the width of street.
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Hey there!
Let's take the hypotenuse to be 17m. So, perpendicular= 8m
We have to find the base.
b^2 = h^2 - p^2
= 17^2 - 8^2
= 289 - 64
= 225
b = 15m
Now for the other side:
b^2 = h^2 - p^2
= 17^2 - 15^2
= 289 - 225
= 64
b = 8m
Width of street = 8+15 m
= 23 m
Therefore, the width of the street is 23m.
Hope it helps!!
Let's take the hypotenuse to be 17m. So, perpendicular= 8m
We have to find the base.
b^2 = h^2 - p^2
= 17^2 - 8^2
= 289 - 64
= 225
b = 15m
Now for the other side:
b^2 = h^2 - p^2
= 17^2 - 15^2
= 289 - 225
= 64
b = 8m
Width of street = 8+15 m
= 23 m
Therefore, the width of the street is 23m.
Hope it helps!!
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