If a ladder weighing 250N is placed against a smooth vertical wall having coefficient of friction between it and floor 0.3 ,then what is the maximum force of friction available at the point of contact between the ladder and the floor
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7
for equilibrium of ladder, maximum force of friction available at a point of contact
between the ladder and floor=mew r
mew r = 0.3*250
=75N
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Answered by
3
Answer:
The answer is 75N
Explanation:
For this, you just have to multiply 0.3 by 250N.
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